🔚 ΠroDriveArts

🔚[Π'ro/Drive:-Arts] : (11/9π↔9/11Π)

[(system)] Sin(Πl/πRO),Cos(Πl/πRO)

Z∫ { Πl - [ Πl^(2n+1) / (2n+1)! ] } / 7

· { 1 - [ Πl^(2n+0)i / (2n+0)! · i ] } / 5

/ 6[ Πli - { Πl^(4n+1)i / (4n+1)! · i }^2 ] · 12/7

 

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過伸縮傾向ではあるが定位がズレた時用の
一方アクセラレートスキル(11/9π↔9/11Π)

Sin(Πl/πRO),Cos(Πl/πRO)

{Πl-[Πl^(2n+1)/(2n+1)!]}/7·

{1-[Πl^(2n+0)i/(2n+0)!·i]}/5/

6{[Πli-[Πl^(4n+1)i/(4n+1)!·i]]^2}·12/7

Ｚ∫ [ZET INTEGRAL]

z∫ = ∫(a(Z)~b(ZA))

Z[(DE!)]

A[1-(2DE!)]

D = [(anc·enc)^3]

E = [(enc·anc·enc)^2]

2·Σ(∞)[k=0] {[n]·[1/n]}

{[1·1] / [(n+1)^[k0]^[k1]]}

3·Σ(∞)[k=0] {[1/n]·[n]·[1/n]}

{[1·1·1] / [(n+1)^[k0]^[k1]^[k2]]}

xＺ∫ [CANNOT ZET INTEGRAL]

z∫ = ∫(a(Z)~b(ZA))

Z[(DE!)]

A[1-(2DE!)]

DE = 2[DivF(anc·enc)]

Σ(∞)[k=0] {([n]·[1/n])^[([k][k+1])[

[If(k+6)(MOD5)];[k+5])}

ゼットインテグラの何が特別なのか、
ってZとZAを底に、切片の足跡を辿れるからだよ

Z[(DE!)]

A[1-(2DE!)]

Zを底に積み上げるからな